SOLUTION: 1. graph the line that passes through(-2,-3) and has a slope -1/2. 2. graph 2x-3y=-3

Algebra ->  Linear-equations -> SOLUTION: 1. graph the line that passes through(-2,-3) and has a slope -1/2. 2. graph 2x-3y=-3      Log On


   

Question 196072: 1. graph the line that passes through(-2,-3) and has a slope -1/2.
2. graph 2x-3y=-3
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


1. graph the line that passes through(-2,-3) and has a slope -1/2.

Via Slope-Intercept Form:
y=mx%2Bb
-3=%28-1%2Fcross%282%291%29%28cross%28-2%29-1%29%2Bb ---> -3=%28-1%29%28-1%29%2Bb
-3=1%2Bb
b=-3-1=red%28-4%29, Y-Intercept

It follows ----> red%28y=%28-1%2F2%29x-4%29 or
In Std.Form, %281%2F2%29x%2By=-4, multiply by 2
red%28x%2B2y=-8%29

Let Fy=0
x%2B2%280%29=-8
red%28x=-8%29, X-Intercept


2. graph 2x-3y=-3

Let Fy=0
2x-3%280%29=-3--->cross%282%29x%2Fcross%282%29=-3%2F2
red%28x=-3%2F2%29, X-Interecpt (-3/2,0) or (-1.5,0)

Let Fx=0
2%280%29-3y=-3 ---> cross%28-3%29y%2Fcross%28-3%29=cross%28-3%291%2Fcross%28-3%291
red%28y=1%29



Thank you,
Jojo