SOLUTION: Rationalize the denominator 2/(square root[6] - square root [5]) If you could help me with this, i would appreciate it.

Algebra ->  Radicals -> SOLUTION: Rationalize the denominator 2/(square root[6] - square root [5]) If you could help me with this, i would appreciate it.       Log On


   

Question 195955: Rationalize the denominator
2/(square root[6] - square root [5])
If you could help me with this, i would appreciate it.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
2%2F%28sqrt%286%29-sqrt%285%29%29 Start with the given expression.


Multiply both the numerator and denominator by sqrt%286%29%2Bsqrt%285%29


%282%28sqrt%286%29%2Bsqrt%285%29%29%29%2F%28%28sqrt%286%29%29%5E2-%28sqrt%285%29%29%5E2%29 FOIL the denominator (use the difference of squares formula)


%282%28sqrt%286%29%2Bsqrt%285%29%29%29%2F%286-5%29 Square each term.


%282%28sqrt%286%29%2Bsqrt%285%29%29%29%2F%281%29 Combine like terms.


2%28sqrt%286%29%2Bsqrt%285%29%29 Reduce


2%2Asqrt%286%29%2B2%2Asqrt%285%29 Distribute


So 2%2F%28sqrt%286%29-sqrt%285%29%29=2%2Asqrt%286%29%2B2%2Asqrt%285%29