SOLUTION: I have a right triangle with the letters "ACB" (C being 90*) the sides of the triangle are lettered "bac". bc make up the right triangle. using the variables given and the definiti

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Question 195466: I have a right triangle with the letters "ACB" (C being 90*) the sides of the triangle are lettered "bac". bc make up the right triangle. using the variables given and the definition of sine and cosine ratios. Show that tanA = sinA / cosA
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Def for sineA = a/c
Def for cosineA = b/c
Def tangentA = a/b
tangentA+=+a%2Fb
tangentA+=+%28a%2Fb%29+%2A%28%281%2Fc%29%2F%281%2Fc%29%29
tangentA+=++%28%28a%2Fc%29%2F%28b%2Fc%29%29
tangentA+=++sineA%2FcosineA