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| Question 195292:  In a family there are two cars. In a given week, the first car gets an average of 30 miles per gallon, and the second car gets 40 miles per gallon. The two cars combined drive a total of 2500 miles in that week, for a total gas consumption of 70 gallons. How many gallons were consumed by each of the two cars that week?
 Answer by checkley77(12844)
      (Show Source): 
You can put this solution on YOUR website! x/30+(2,500-x)/40=70 (40x+30(2,500-x))/(30*40)=70
 (40x+75,000-30x)/1,200=70
 10x+75,000=70*1,200
 10x+75,000=84,000
 10x=84,000-75,000
 10x=9,000
 x=9,000/10
 x=900 miles for the 30 mpg car.
 2500-900=1,600 for the 40 mpg car.
 Proof:
 900/30+1,600/40=70
 30+40=70
 70=70
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