SOLUTION: Please let me know if this is correct. Question: Given the equation of a circle is x2+y2-10x+4y+13=0, find its centerand its radius. Answer: x2-10x+25+y2+4y+4=-3+25+4 (x-5)

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Please let me know if this is correct. Question: Given the equation of a circle is x2+y2-10x+4y+13=0, find its centerand its radius. Answer: x2-10x+25+y2+4y+4=-3+25+4 (x-5)      Log On


   



Question 195023: Please let me know if this is correct.
Question: Given the equation of a circle is x2+y2-10x+4y+13=0, find its centerand its radius.
Answer:
x2-10x+25+y2+4y+4=-3+25+4
(x-5)2 +(y+2)2=16
Center (5,-2)
Radius 6

Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
Good Job,,, with just very minor mods
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in line " -3 +25+4" should be "-13 +25 +4",,,,,,just a typo,,,next line is correct
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form is correct,, except 16 is r^2,,,therefore r=4
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Keep up good work