You can put this solution on YOUR website! Let x = the 10's digit
Let y = the units
then
10x + y = the two digit number
;
"The product of a two-digit number and its tens digit is 285".
x(10x + y) = 285
:
" The units digit is two more than the tens digit."
y = x+2
:
Substitute (x+2) for y in the 1st equation
x(10x + (x+2)) = 285
:
x(11x + 2) = 285
:
11x^2 + 2x = 285
:
11x^2 + 2x - 285 = 0; a quadratic equation
Factors to:
(11x + 57)(x - 5) = 0
Positive solution
x = 5
then
y = 5 + 2
y = 7
:
the original number = 57
;
:
Check solution:
5(10(5) + 7) =
5(57) = 285