Question 194848: I have 10 problems and I have four possible answers to all of them but I am not sure which one it might be. The answer choices would be labeled A, B, C, and D. I would really appreciate it if I can get it really soon. thankyou you guys soooooooo much! :)
Solve by using the perfect squares method.
x2 + 4x + 4 = 0
(Points: 4)
A. 2
B. -2
C. 4
D. - 4
2. Solve.
x2 + 5x 6 = 0
(Points: 4)
A. {2, 3}
B. {-2, -3}
C. {-1, 6}
D. {1, -6}
3. What value should be added to the expression to create a perfect square?
x2 20x
(Points: 4)
A. - 25
B. 25
C. 100
D. -100
4. Solve.
x2 + 8x 8 = 0
(Points: 4)
Option A: -4 +/- 2 & square root of 12
Option B: -4 +/- 2 & square root of 6
Option C: -4 +/- & square root of 6
Option D: 4 +/- & square root of 12
5. Solve: 6x2 + 12x = 0
(Points: 4)
{-6, -2}
{0, ½}
{0, 2}
{0, -2}
6. Solve each problem by using the quadratic formula. Write solutions in simplest radical form.
2x2 - 2x -1 = 0
(Points: 4)
I have no option ABC or D, I just need the answer. :)
7. Calculate the discriminant.
x2 - x + 2 = 0
(Points: 4)
9
A.
7
B.
- 7
C.
- 9
D.
8. Calculate the discriminant and use it to determine how many real-number roots the equation has.
3x2 - 6x + 1 = 0
(Points: 4)
A. three real-number roots
B. two real-number roots
C. one real-number root
D. no real-number roots
9. Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
y = 2x2 + x + 3
(Points: 4)
A. 1 point in common; vertex on x-axis
B. 2 points in common; vertex below x-axis
C. 2 points in common; vertex above x-axis
D. no points in common; vertex below x-axis
10. Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
y = 3x2 - 12x + 12
(Points: 4)
A. 1 point in common; vertex on x-axis
B. 2 points in common; vertex below x-axis
C. 2 points in common; vertex above x-axis
D. no points in common; vertex above x-axis
Answer by solver91311(24713)   (Show Source):
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