SOLUTION: the perimeter of a lot is 190 m. the length os four times the width. find the length and the width?

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: the perimeter of a lot is 190 m. the length os four times the width. find the length and the width?      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 194794: the perimeter of a lot is 190 m. the length os four times the width. find the length and the width?
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


Let x represent the width. Then 4x represents the length. The perimeter of a rectangle is two times the width plus two times the length:



Solve for x to get the width, multiply that by 4 to get the length.

John