Question 194785: i have to write an equation of the line that is tangent to the circle at that point:
x^2+y^2=50; (-7,1) Found 2 solutions by Edwin McCravy, josmiceli:Answer by Edwin McCravy(20056) (Show Source):
You can put this solution on YOUR website! i have to write an equation of the line that is tangent to the circle at that point:
x^2+y^2=50; (-7,1)
Find the derivative by the method of implicit functions
Substitute (x,y)=(-7,1)
Therefore the slope, m, of the tangent line
at (-7,1) is 7. So m=7
Now we use the point-slope form of the
equation of a line:
To check it we draw the equation of the circle
and the line:
Edwin
You can put this solution on YOUR website! First, answer the question: "Is the point (-7,1)
on the circle?" Yes
The center of the circle is the origin.
Next find the equation of the line that
contains the points (0,0) and (-7,1)
Multiply both sides by
This is of the form , and is the slope
Any line perpendicular to this one will have slope , in this case,
So, the line tangent to the circle at (-7,1) will have
slope = . answer
I'll plot the circle and the line
