SOLUTION: A wire 20 feet long is to be cut into two pieces. one pierce will be shaped as a square and the other piece will be shaped as an equilateral triangle. express the total area A encl

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Question 194553: A wire 20 feet long is to be cut into two pieces. one pierce will be shaped as a square and the other piece will be shaped as an equilateral triangle. express the total area A enclosed by by the piece of wire as a function of the length x of a side of the equilateral triangle. what is the domain of A? for what value of x will the total area A be the smallest?
please i need help. please help me please.....

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
If x is a side of the equilateral triangle,
then the length of wire used for the triangle is
3x ft
The length of wire left over for the square is
20+-+3x ft
One side of that square would be
%2820+-+3x%29%2F4 ft
If A is the total area, then
A+=+sqrt%283%29%2A%28x%2F2%29%5E2+%2B+%28%2820+-+3x%29%2F4%29%5E2
A+=+sqrt%283%29%2A%28x%2F2%29%5E2+%2B+%28%2820+-+3x%29%2F4%29%5E2
A+=+%28%28sqrt%283%29%29%2F4%29%2Ax%5E2+%2B+%28400+-+120x+%2B+9x%5E2%29+%2F+16
Multiply both sides by 16
16A+=+4%2Asqrt%283%29%2Ax%5E2+%2B+%28400+-+120x+%2B+9x%5E2%29%2F16
A+=+%28sqrt%283%29%2F4+%2B+9%29%2Ax%5E2+-+120x+%2B+400
-------------------------------------------
If x+=+0, or I had no triangle at all, then
A+=+400, as it should, since the whole 20 ft
is being used by the squareand A+=+20%5E2
If x+=+20%2F3, then nothing is left for the square, and
all the area is used by the triangle.
I'll check this:
A+=+sqrt%283%29%2A%28x%2F2%29%5E2+
A+=+1.732%2A%2820%2F6%29%5E2
A+=+1.732%2A11.111
A+=+19.244 ft2
and
A+=+%28sqrt%283%29%2F4+%2B+9%29%2Ax%5E2+-+120x+%2B+400
A+=+%28sqrt%283%29%2F4+%2B+9%29%2A%2820%2F3%29%5E2+-+120%2A%2820%2F3%29+%2B+400
A+=+%28sqrt%283%29%2F4+%2B+9%29%2A%28400%2F9%29+-+800+%2B+400
A+=+100%2Asqrt%283%29%2F9+%2B+400+-+800+%2B+400+
A+=+19.244 ft2
The domain of A is 19.244 < A < 400
--------------------------------------------
When an equation is of the form
ax%5E2+%2B+bx+%2B+c, the minimum is at x+=+-%28b%2F%282a%29%29
In this case,
b+=+-120
a+=+sqrt%283%29%2F4+%2B+9
-%28b%2F%282a%29%29+=+-%28-120%29%2F%282%2A%28sqrt%283%29%29%2F4+%2B+18%29
-%28b%2F%282a%29%29+=+120+%2F+18.866
-%28b%2F%282a%29%29+=+6.361 ft
This is the value of x for which A is a minimum
I'll graph the function to check this (approximately)
+graph%28+500%2C+500%2C+-5%2C+16%2C+-15%2C+450%2C+9.433x%5E2+-+120x+%2B+400%29+
And here's a close-up
+graph%28+600%2C+600%2C+-2%2C+9%2C+-5%2C+25%2C+9.433x%5E2+-+120x+%2B+400%29+