You can put this solution on YOUR website! How many gallons of a %15 acid solution must be mixed with 5gal.
of a %20 solution to make a %16 solution?
:
Let x = amt of 15% solution required
:
A decimal amt of acid mixture equation:
:
.15x + .20(5) = .16(x+5)
:
.15x + 1 = .16x + .8
:
1 - .8 = .16x - .15x
:
.2 = .01x
x =
x = 20 gal of 15% solution required
:
:
Check solution in original equation
.15(20) + .20(5) = .16(20 + 5)
3 + 1 = 4; confirms our answer