Question 1944: Find each quotient: The problem below is a fraction with 3 sets of numbers on top and three on bottom.
6a^5b^7c^6/-3a^3b^9c^6 Answer by longjonsilver(2297) (Show Source):
You can put this solution on YOUR website!
this becomes...
since you just subtract the powers...so
for a: 5-3=2
for b: 7-9=-2...therefore 2 on the bottom
for c: 6-6=0...they cancel each other
jon.