SOLUTION: a piece of bone from an organism is found to contain 10% of the carbon- 14 that it contained when the organism was living. if the half- life of carbon -14 is 5730 years then how lo
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Question 194260: a piece of bone from an organism is found to contain 10% of the carbon- 14 that it contained when the organism was living. if the half- life of carbon -14 is 5730 years then how long ago was the organism was alive?
please i need help!!!!!
i really dont know how to solve help please... Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! the half-life of carbon-14 is 5730yr
this means that in 5730yr, 50% of the original amount will remain
in another 5730yr, 25% will remain
and so on
the number of half-lives can be found from ___ p = (1/2)^n
where p is the fraction remaining and n is the number of half-lives
taking the log ___ log(p) = n * log(1/2)
dividing by log(1/2) ___ [log(p)] / [log(1/2)] = n
[log(.10)] / [log(1/2)] = n
using a calculator ___ n = 3.32 (approx)
so the time is ___ 3.32 * 5730 = 19024yr
