SOLUTION: Please help me solve this equation: {{{ 2x^2+20x+50=0 }}} I tried working it out several times but was unable to understand why the end result was {{{ (x+5)(x+6) }}} instead of

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Please help me solve this equation: {{{ 2x^2+20x+50=0 }}} I tried working it out several times but was unable to understand why the end result was {{{ (x+5)(x+6) }}} instead of      Log On


   



Question 194150This question is from textbook Saxon Algebra 1
: Please help me solve this equation: +2x%5E2%2B20x%2B50=0+
I tried working it out several times but was unable to understand why the end result was +%28x%2B5%29%28x%2B6%29+ instead of +2%28x%2B5%29%28x%2B6%29+. What happened to the '2', and why and how am I supposed to get rid of it?
Thank you so much for your help!
This question is from textbook Saxon Algebra 1

Answer by RAY100(1637) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2 + 20x +50 = 0
Let's divide thru each term, on both sides by 2,,,this should not change the expression
x^2 +10x +25 = 0
factor
(x+ 5 ) ( x + 5 ) =0
x+5 = 0, therefore x=-5, and -5,,,,,,,,
checking
2(-5)^2 + 20 (-5) +50 =0
50 -100 +50 = 0
100 = 100,,,,,,ok
,
You were right to be concerned about the (2), but as you see, a constant thruout the
equation, just makes all the numbers larger.
,
Again think of an equation like a balance, or a tee- ter - totter, you can add, subtract, multiply or divide both sides equally, and the balance is maintained.