Question 194128This question is from textbook
: how would you find the foci of this ellipse?
x^2+9y^2=1
This question is from textbook
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! The standard form of an ellipse is: x^2/a^2 + y^2/b^2 = 1
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and the foci are at (+/-c,0 ) where c^2 = a^2 - b^2
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We might need to review your problem,
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It might be better if it were: x^2 +9y^2 = 9
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dividing by 9
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x^2 /9 +y^2/1 =1,,,,,,now fits form with a^2=9,,,,a=3, b=1
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now foci are ,,, c^2 = a^2 - b^2,,, c^2 = 9 - 1 = 8,,,, c = +/- 2.83
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foci located at (2.83,0),,,,and (-2.83,0)
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again pls check original problem, thanks
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