SOLUTION: I do not understand how to solve these. Any help would be appreciated. {{{ x^2-3x-18=0 }}}

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I do not understand how to solve these. Any help would be appreciated. {{{ x^2-3x-18=0 }}}      Log On


   

Question 19402: I do not understand how to solve these. Any help would be appreciated.
+x%5E2-3x-18=0+
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
You could try factoring the polynomial.
x%5E2+-+3x+-+18+=+0 You need to find two integers whose product is -18 and whose sum is -3. (x + ? )(x + ?)
Try 3 X -6 = -18
3 + (-6) = -3
%28x+%2B+3%29%28x+-+6%29+=+0 = x%5E2+-+3x+-+18+=+0 So these are the correct factors.
%28x+%2B+3%29%28x+-+6%29+=+0 Apply the zero products principle.
(x + 3) = 0 and/or (x - 6) = 0
If x + 3 = 0 then, x = -3
If x - 6 = 0 then, x = 6
The roots are:
x = -3
x = 6