SOLUTION: I really appreciate your help. I am having a hard time solving this problem. The function f(x) =70 square root x models the number of calories per day, f(x), a person needs to m

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: I really appreciate your help. I am having a hard time solving this problem. The function f(x) =70 square root x models the number of calories per day, f(x), a person needs to m      Log On

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Question 19391: I really appreciate your help. I am having a hard time solving this problem.
The function f(x) =70 square root x models the number of calories per day, f(x), a person needs to maintain life in terms of the person's weight, x, in kilograms.
How many calories does a person who weighs 51 kilograms (approxmiately 112.3 pounds) need to maintain life?
Round to the nearest whole number.
Thanks for your help.

Answer by wuwei96815(245) About Me  (Show Source):
You can put this solution on YOUR website!
I am not sure that I understand the problem, but let me give it a try.

f(x) = 70 times square root of x where f(x)=calories need and x=weight in kilograms.

f(x) = 70 times (square root of 51) = 70 times (7.14) = 499.89 = 500 calories