Question 19390: 1. Bill has $2.05 in dimes and quarters. If he has four more quarters than dimes. Find the number he has of each coins.
2. Hilda deposited in her saving accunt $4.50 in nickels, dimes and quarters. If the number of dimes exceeded the number of nickels by five, and the number of quarters was ten less than the number of nickels. Find the number of each kind of coins she deposited.
3. Harry has $2.30 in Nickels and dimes. The number of dimes is seven less than the number of nickels. Find the number he has of each coin.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! All these problems are essentially the same.
You have quantity data regarding number of different kinds of coins.
And you have value data: e.g. x nickels are worth 5x cents.
Look at your problem #1.
Read it carefully. Look for quantity information. Look for value information.
The quantity info. indicates there are fewer dimes than quarters.
Let the number of dimes by "x".
Then number of quarters is "x+4"
The value of the dimes is 10xcents
The value of the quarters is 25(x+4)=25x+100
Equation:
The $2.05 is a value idea.
Value of dimes + Value of quarters is 205cents
10x + 25x+100 = 205
35x = 105
x = 3 (# of dimes)
x+4 = 7 (# of quarters)
Try these ideas on your other two problems. Maybe you can
work them out yourself.
Cheers,
Stan H.
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