SOLUTION: let log2=0.03+log3=0.05 find log(3/2)
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-> SOLUTION: let log2=0.03+log3=0.05 find log(3/2)
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Question 193874
:
let log2=0.03+log3=0.05 find
log(3/2)
Answer by
nerdybill(7384)
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Applying log rules:
let log2=0.03+log3=0.05 find
log(3/2)
.
log(3/2)
can be rewritten as:
log(3) - log(2)
then, replace with given values:
0.05 - 0.03 = 0.02