SOLUTION: a retailer spent $48 to purchase a number of special mugs. Two of them were broken in the store, but by selling each of the remaining mugs for $3 above the original cost per mug, s

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: a retailer spent $48 to purchase a number of special mugs. Two of them were broken in the store, but by selling each of the remaining mugs for $3 above the original cost per mug, s      Log On


   

Question 193790: a retailer spent $48 to purchase a number of special mugs. Two of them were broken in the store, but by selling each of the remaining mugs for $3 above the original cost per mug, she made a total profitt of $22. If the price for the n mugs is $48, how can we express the cost per mug? Now have to write in standard form of a quadratic equation
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!

If n cups cost x each and the total cost was $48, then the cost per cup must be dollars.

The revenue from the sales of all but two of the cups given a $3 mark-up must then be:



And if the profit is $22, then the total revenue must be $48 + $22 = $70, so:



Multiply:





Multiply by n



The positive root will be the number of cups purchased.

John