Question 193741: I just found this website and I hope someone can help me with a real problem, problem.
In 1992 the life expectancy of males in a certain country was 72.5 yrs. In 1997, it was 75.3 yrs. Let e represent the life expectancy in year t and let t represent the number of years since 1992.
Thank-you
Found 2 solutions by user_dude2008, RAY100:
Answer by user_dude2008(1862)   (Show Source):
Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website! Usually we assume "exponential growth"
This follows,,,y=C(1+r)^t,,,where C is initial amount,, r is rate,,and t is time
Using the given data
y(0) = C (1+r)^0 = 72.5
but as (1+r)^0 =1
C=72.5
,
y(5) = 72.5 (1+r)^5 =75.3
(1+r)^5=75.3/72.5 = 1.03862
taking 5th root
(1+r) = 1.0076
r= .0076
,
the general expression is
,
e = 72.5 (1.0076) ^t
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