SOLUTION: log4(x)+log4(x-6)=2

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Question 193652: log4(x)+log4(x-6)=2
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
log4(x)+log4(x-6)=2
log4((x)(x-6))=2
(x)(x-6)=4^2
(x)(x-6)=16
x^2-6x=16
x^2-6x-16=0
(x-8)(x+2) = 0
.
x = {-2, 8}
Throw out the negative solution (can't have log of negatives):
x = 8