SOLUTION: Mr. Logarithmic is showing his class a solution to a problem. Is Mr. Logarithmic correct? Explain and correct if he is incorrect. Express 2log25 - log2(4/5) + 1/2log216 as a single
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-> SOLUTION: Mr. Logarithmic is showing his class a solution to a problem. Is Mr. Logarithmic correct? Explain and correct if he is incorrect. Express 2log25 - log2(4/5) + 1/2log216 as a single
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Question 193635: Mr. Logarithmic is showing his class a solution to a problem. Is Mr. Logarithmic correct? Explain and correct if he is incorrect. Express 2log25 - log2(4/5) + 1/2log216 as a single logarithm = 2log25 - log2(4/5) + 1/2log216 = log252 - log2(4/5) + log2(16/2) = log225 - log2(4/5) + log2(8) = log2(25 × 4/5 × 8)
You can put this solution on YOUR website! Express 2log25 - log2(4/5) + 1/2log216 as a single logarithm
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Is it base 2? If so,
= log(25 /(4/5)) + log(sqrt(216))
= log((125/4)*sqrt(216))
= log((750/4)*sqrt(6))
=
