Question 19352:  -2X-5>=-15 
-8<=-5+1/3X 
5-2X>2X+21 
WHAT WOULD THE 7TH NUMBER NEED TO BE IN ORDER TO HAVE A MEAN OF EXACTLY 250 PEOPLE IN ATTENDANCE? 203,256,211,225,276,200 
 Answer by venugopalramana(3286)      (Show Source): 
You can  put this solution on YOUR website! WHAT WOULD THE 7TH NUMBER NEED TO BE IN ORDER TO HAVE A MEAN OF EXACTLY 250 PEOPLE IN ATTENDANCE? 203,256,211,225,276,200 
let the 7th.number =x 
so mean =sum of all 7 numbers /7=(203+256+211+225+276+200+x)/7=250 
(203+256+211+225+276+200+x)=7*250=1750 
x=1750-(203+256+211+225+276+200)=1750-1371=379 
so the 7th.number is 379 
REGARDING INEQUALITIES SEE FOLLOWING EXAMPLES SOLVED BY ME EARLIER AND DO YOUR SELF.IF STILL THERE IS DIFFICULTY COME BACK 
Graphs/17660: 2<5-2x/3<7 
1 solutions
 
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Answer 8553 by venugopalramana(298)   on 2005-10-30 11:25:19 (Show Source): 
 
2<5-2x/3<7..take one by one to solve 
2<5-2x/3 
2x/3<5-2=3 
x<3*3/2 
x<9/2 
5-2x/3<7 
5-7<2x/3 
-2<2x/3...or..-2*3/2<1*x...or.....-3<1*x  
....so the answer is -3<1*x<9/2 
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Graphs/17965: how do you solve eniqualities 
1 solutions
 
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Answer 8675 by venugopalramana(298)   on 2005-11-01 11:13:46 (Show Source): 
 
the rules of transformations between equalities and inequalities are same but for few exceptions..they are given below..use them to solve the inequalities 
...........property..............equality....inequality.......conclusion 
...example........................3+2=5.......5<8 
1.reverse sides.left to right ...5=3+2......8>5..inequality changes from < to >  
2.multiply/divide with -ve number.-5=-(3+2)..-5>-8 same as above......... 
3.take reciprocal.................1/(3+2)=1/5..1/5>1/8..same as above.. 
so take care of these and solve 
1example...x+5>8..or x>8-5=3..or x>3 
2.3>5+x..or x+5<3..or x<3-5=-2..or x<-2..(exception rule no.1 above) 
2.example...-x+5>8..or-x>8-5=3..or -x>3..or x<3(exception rule no2. above) 
3.example...1/x>1/8...or x<8....(exception rule no.3 above) 
SO BE CAREFULL IN THESE OPERATIONS..PARTICULARLY MULTIPLICATION/DIVISION WITH UNKNOWNS..YOU HAVE TO BE SURE WHETHER IT IS A +VE NUMBER OR _VE NUMBER
 
 
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