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| Question 193460:  How do I solve the inequality x^3-x^2-6x>0?
 Answer by stanbon(75887)
      (Show Source): 
You can put this solution on YOUR website! solve the inequality x^3-x^2-6x > 0 ---------
 Factor to find values that x cannot have:
 x(x^2-x-6) > 0
 x(x-3)(x+2) > 0
 x cannot be 0, 3 or -2
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 Draw a number line and plot x = -2, 0, and 3
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 Test a value in each of the four resulting intervals to
 see where solutions are for the inequality:
 Test x = -5, you get (-5)^3-(-5)^2-6(-5) > 0 which is false
 Test x = -1, you get (-1)^3-(-1)^2-8(-1) > 0 which is true
 Test x = 1, you get 1 -1 - 6 > 0 which is false
 Test x = 5, you get (5)^3 - (5)^2 -6(5) > 0 which is true
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 Solutions are in -2 < x < 0 and 3 < x < +inf
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 Cheers,
 Stan H.
 
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