Question 193387:  Please check my work, thank you.
 
Practical Application of Quadratic Equations 
 
 
1.	A rectangular garden has dimensions of 15 feet by 11 feet. A gravel path of uniform width is to be built around the garden. How wide can the path be if there is enough gravel for 192 square feet?  
Ag = area of garden = 15 * 11 = 165 sq feet
 
Ap = area of gravel path = (15 + 2x)(11 + 2x) - 165
 
Ap = 165 + 52x + 4x^2 - 165
 
Ap = 4x^2 + 5x
 
where
 
x = width of the gravel path around the garden
 
and since the available gravel is 192 sq ft, then the above equation becomes
 
4x2 + 5x = 192
 
and rewriting,
 
4x2 + 5x - 192 = 0
 
Using the quadratic formula,
 
x = 6.33 feet
 
ANSWER: The width of the gravel path should be about 6' 4". 
              
2.	A business invests $8,000 in a savings account for two years.  At the beginning of the second year, an additional $2,500 is invested.  At the end of the second year, the account balance is $11,445.  What was the annual interest rate? 
 
the annual interest rate = r  
$8,000 in a savings account for two years.--> 8000*(1+r)^2 
beginning of the second year, an additional $2,500 is invested-->2500*(100+r) 
8000*(1+r)^2 + 2500*(1+r) = 11,445 
suppose 100+r = A 
8000*A^2 + 2500*A = 11,445 
8000*A^2 + 2500*A - 11,445 = 0 
A = 1.05 
r = 0.05 or 5 % Ans.
 
3.	Steve traveled 150 miles at a certain speed. Had he gone 20mph faster, the trip would have taken 2 hours less. Find the speed of his vehicle. 
 
Let R = rate of Steve 
150/R  150/(R + 20) = 2 
150(R+ 20)  150(R) = 2(R)(R + 20) 
150R + 3000  150R = 2Rē + 40R 
0 = 2Rē + 40R  3000  
Rē + 20R  1500 = 0 
(R + 50)(R  30) = 0 
(R + 50) = 0 
R = 50 Discard, negative rate 
(R  30) = 0 
R = 30 mph (speed of vehicle)
 
 
  
4.	The Hudson River flows at a rate of 5 miles per hour.  A patrol boat travels 40 miles upriver, and returns in a total time of 6 hours.  What is the speed of the boat in still water? 
Let R = rate of patrol boat 
40/(R  5) + 40(R + 5) = 6 
40(R + 5) + 40(R + 5) = 6(R + 5)(R  5) 
40R  200 + 40R + 200 = 6Rē  150 
0 = 6Rē  80R  150 
3Rē  40R  75 = 0 
(3R + 5)(R  15) = 0 
(3R + 5) = 0 
3R = 5 
R = 5/3 Discard, negative rate 
(R  15) = 0 
R = 15 mph (speed of boat in still water) 
 Answer by yuendatlo(23)      (Show Source): 
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