SOLUTION: Find the vertex, focus, directrix, and axis of symmetry of each parabola.
We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, e
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Quadratic-relations-and-conic-sections
-> SOLUTION: Find the vertex, focus, directrix, and axis of symmetry of each parabola.
We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, e
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We have been using the formulas y-k=a(x-h)^2 and x-h=a(y-k)^2 I don't understand which to use here, even after completing the square and its confusing because I don't know which is which. please explain and be specific. thank you. This question is from textbook algebra and trigonometry structure and method book 2
You have to share the specific problems if you want specific help. But in general, if x is the squared variable, the parabola opens either up or down (up if a is positive, down if negative). If y is the squared variable, it opens right or left (right if a is positive, left if a is negative).
