SOLUTION: Hi Tutor,
I am stuck on this problem. ln(x+2)-ln(4)=-ln x
Do I take the ln of 2 and subtract the ln of 4? I don't know what else to do to solve thi1s.
Thank you
Question 193260This question is from textbook Basic Technical Mathematics
: Hi Tutor,
I am stuck on this problem. ln(x+2)-ln(4)=-ln x
Do I take the ln of 2 and subtract the ln of 4? I don't know what else to do to solve thi1s.
Thank you This question is from textbook Basic Technical Mathematics
You can put this solution on YOUR website! Apply log rules:
ln(x+2)-ln(4)=-ln x
ln(x+2)-ln(4)+ln x = 0
ln[(x+2)/(4)]+ln x = 0
ln[x(x+2)/(4)] = 0
x(x+2)/(4) = e^0
x(x+2)/(4) = 1
x(x+2) = 4
x^2 + 2x = 4
x^2 + 2x - 4 = 0
Solve using the quadratic equation. Doing so yields:
x = {1.236, -3.236}
.
We can throw out the negative solution, leaving:
x = 1.236
.
Details of quadratic to follow:
