SOLUTION: We are learning about "f of g" (fog as the teacher calles it) and "g of f" (gof as the teacher calles it)! Please explain the procedure for this!
Perform the following operatio
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-> SOLUTION: We are learning about "f of g" (fog as the teacher calles it) and "g of f" (gof as the teacher calles it)! Please explain the procedure for this!
Perform the following operatio
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Question 19322: We are learning about "f of g" (fog as the teacher calles it) and "g of f" (gof as the teacher calles it)! Please explain the procedure for this!
Perform the following operation on the listed problem (a) f of g, & (b) g of f;
f(x) = 2x + 1 g(x) = 3x - 2
Thank you so much!
Sheri Answer by Earlsdon(6294) (Show Source):
You can put this solution on YOUR website! "f o g" is an abreviation of...f(g(x))
"g o f" is an abreviation of...g(f(x))
If f(x) = 2x+1 and g(x) = 3x-2, then:
f o g = f(g(x)) = f(3x-2) = 2(3x-2)+1 = 6x-4+1 = 6x-3
g o f = g(f(x)) = g(2x+1) = 3(2x+1)-2 = 6x+3-2 = 6x+1
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