SOLUTION: Hello Tutor, The directions is to solve the equation. 4log4+logx=6 I have log4^4+6logx here is where I am having trouble.

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Question 193123This question is from textbook Basic Technical Mathematics
: Hello Tutor,
The directions is to solve the equation. 4log4+logx=6
I have log4^4+6logx here is where I am having trouble. This question is from textbook Basic Technical Mathematics

Found 2 solutions by nerdybill, RAY100:
Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website!
Solve using "log rules":
4log4+logx=6
log4^2+logx=6
log16+logx=6
log(16x)=6
16x = 10^6
x = 10^6/16
x = 62500

Answer by RAY100(1637) (Show Source):
You can put this solution on YOUR website!
4log4+logx=6
log4^4+logx=6
to add logs is to multiply
log (4^4*x)=6
log256x=6
raise to power of base 10
10^log(256x)=10^6
256x=10^6=1000000
x=1000000/256=3906.25
check
4log4+log3906.25=6
2.4082+3.5918=6
6=6