SOLUTION: I need help with this problem. Directions is solve for y in terms of x.
log10y = log10 7-3 log10(x-7). This is what I have done.
log10y = log10 7-3 log10 (x-7). I canceled out
Algebra ->
Logarithm Solvers, Trainers and Word Problems
-> SOLUTION: I need help with this problem. Directions is solve for y in terms of x.
log10y = log10 7-3 log10(x-7). This is what I have done.
log10y = log10 7-3 log10 (x-7). I canceled out
Log On
Question 193116This question is from textbook Basic Technical Mathematics
: I need help with this problem. Directions is solve for y in terms of x.
log10y = log10 7-3 log10(x-7). This is what I have done.
log10y = log10 7-3 log10 (x-7). I canceled out the log10 and was left with.
y=x/3 then convert to y=x3. Is this correct? This question is from textbook Basic Technical Mathematics
You can put this solution on YOUR website! Directions is solve for y in terms of x.
log10y = log10 7-3 log10(x-7). This is what I have done.
log10y = log10 7-3 log10 (x-7). I canceled out the log10 and was left with.
y=x/3 then convert to y=x3. Is this correct?
-----------------------
