SOLUTION: Find the vertex,focus,axis, directix andlatus rectum of the paraabola x^2+y=6x-14

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Question 193099: Find the vertex,focus,axis, directix andlatus rectum of the paraabola x^2+y=6x-14
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
y=-%28x%5E2-6x%2B9%29%2B9-14
:
y=-1%28x-3%29%5E2-5
:
vertex is a (3,-5)
:
axis of symmetry is x=3
:
focus is at 1/4a=-1--->-4a=1-->a=-1/4 so focus is at (3,-21/4)
:
latus rectum is abs%284%28-1%2F4%29%29=1