SOLUTION: (2 over b-3 ) - (7 over b^2-3b)
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Question 192851
:
(2 over b-3 ) - (7 over b^2-3b)
Answer by
stanbon(75887)
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(2 over b-3 ) - (7 over b^2-3b)
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2/(b-3) - 7/(b(b-3))
lcd = b(b-3)
= [2b]/lcd - 7/lcd
= [2b - 7]/lcd
= [2b-7]/[b(b-3)]
==========================
Cheers,
Stan H.