SOLUTION: write 3lna-1/2(lnb+lnc^2) as a single logarithm
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Question 192846
:
write 3lna-1/2(lnb+lnc^2) as a single logarithm
Answer by
stanbon(75887)
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write 3lna-1/2(lnb+lnc^2) as a single logarithm
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ln(a^3) - (1/2)ln(bc^2)
ln(a^3) - ln(bc^2)^(1/2)
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= ln[a^3/(b^(1/2)c)]
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Cheers,
Stan H.