SOLUTION: A radioactive substance decays in a way that the amount of mass remaining after (t) days is given by the function: m(t)=5e^(-0.o15*t) What is the mass at time t=0? What is the am

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: A radioactive substance decays in a way that the amount of mass remaining after (t) days is given by the function: m(t)=5e^(-0.o15*t) What is the mass at time t=0? What is the am      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 192802: A radioactive substance decays in a way that the amount of mass remaining after (t) days is given by the function: m(t)=5e^(-0.o15*t)
What is the mass at time t=0?
What is the amount of mass remaining after 43 days?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A radioactive substance decays in a way that the amount of mass remaining after
(t) days is given by the function: m(t) = 5e^(-0.015*t)
:
What is the mass at time t = 0?
When t=0, we have e^0 which we know is = 1, therefore
when t=0, m(t) = 5
:
:
What is the amount of mass remaining after 43 days?
m(t) = 5*e^(-.015*43)
m(t) = 5*e^-.645
:
Find e^-.645 on a good calc
m(t) = 5 * .52466
m(t) = 2.633 after 43 days