SOLUTION: If I have x(x+2)(x-5)
would i really need to solve it to find the interval notation? isn't it (- infinity, -2) U (0,5)... ah I just see that 0,5 cannot be, if so it should be 5, i
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-> SOLUTION: If I have x(x+2)(x-5)
would i really need to solve it to find the interval notation? isn't it (- infinity, -2) U (0,5)... ah I just see that 0,5 cannot be, if so it should be 5, i
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Question 192315: If I have x(x+2)(x-5)
would i really need to solve it to find the interval notation? isn't it (- infinity, -2) U (0,5)... ah I just see that 0,5 cannot be, if so it should be 5, infinity. hm... so do i solve x^2+2x (x-5) which is x^3-5x^2+2x^2-10x but how would I go from here? Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! x^3-3x^2-10x<0
-2, 0 and 5 are inflection points. We have to check on either side of inflection points to see if y is <0 or >0.
if x=-3, then x^3-3x^2-10x=-24
x=-1 then x^3-3x^2-10x=6
x=2 then x^3-3x^2-10x=-24
x=6 then x^3-3x^2-10x=48
x(-infinity, -2)U(0,5)
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Ed
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