SOLUTION: To Solve Integer problems:
The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers.
my try:
Firs
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-> SOLUTION: To Solve Integer problems:
The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers.
my try:
Firs
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Question 192253This question is from textbook Intermediate Algeba
: To Solve Integer problems:
The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers.
my try:
First integer: 3n
Second integer: 8n-3
3n + 8n-3 = 10
11n -3 =10
11n = 13
n = 13/11
Not right?
Help! This question is from textbook Intermediate Algeba
You can put this solution on YOUR website! The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers.
my try:
First integer: 3n
Second integer: 8n-3
3n + 8n-3 = 10
11n -3 =10
11n = 13
n = 13/11
Not right?
Help!
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Not much chance it's right since it's not an integer.
smaller integer = s
bigger integer = b
3b+3 = 8s
b+s = 10 --> s = 10-b
Sub for s into 1st eqn
3b+3 = 8*(10-b)
3b+3 = 80-8b
11b = 77
b = 7
s = 3
You can put this solution on YOUR website! The sum of two integers is ten. Three times the larger integer is three less than 8 times the small integer. Find the integers.
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Equations:
x + y = 10
3x = 8y-3
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Substitute to solve for "x":
3x = 8(10-x)-3
3x = 80 - 8x -3
11x = 77
x = 7 (one of the integers)
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Substitute to solve for "y":
7 + y = 10
y = 3(the other integer)
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Cheers,
Stan H.
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