SOLUTION: 2log4-log3+logx-4=0

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Question 192209: 2log4-log3+logx-4=0
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
2log4-log3+logx-4=0
log4^2-log3+logx-4=0
log(4^2/3)+logx-4=0
log(16/3)+logx-4=0
log(16(x-4)/3)=0
16(x-4)/3 = 10^0
16(x-4)/3 = 1
16(x-4) = 3
x-4 = 3/16
x = 3/16 + 4
x = 3/16 + 64/16
x = 67/16