SOLUTION: Please help me with this algebra 2 problem.
Directions: Using inverses simplify the expression.
#48:5^log x
5
I dont exactly know how to type that but its 5 raise
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Please help me with this algebra 2 problem.
Directions: Using inverses simplify the expression.
#48:5^log x
5
I dont exactly know how to type that but its 5 raise
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Question 192195: Please help me with this algebra 2 problem.
Directions: Using inverses simplify the expression.
#48:5^log x
5
I dont exactly know how to type that but its 5 raised to log is followed by a small 5 thats a little bit lower and next to that a little raised is an x.
I have no idea how to do that but i know that the answer is x could you please explain this to me?
And here is how you would render such a thing as an input to this site:
5^(log(5,(x)))
Now, for the solution to your problem. Remember that:
But notice that in your problem, you are raising 5 to a base-5 logarithm. What means is "the number I would use as an exponent on 5 to equal x" Hence if you raise 5 to the power of the number you would use as an exponent on 5 to equal x, then you would just get x.
