SOLUTION: How to write the equation for the following: 3000 books in three piles. Pile 1 has 10 more books than pile 2. Pile 2 has twice as many as pile 3. How many in each pile? This is m

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: How to write the equation for the following: 3000 books in three piles. Pile 1 has 10 more books than pile 2. Pile 2 has twice as many as pile 3. How many in each pile? This is m      Log On


   



Question 192154: How to write the equation for the following: 3000 books in three piles. Pile 1 has 10 more books than pile 2. Pile 2 has twice as many as pile 3. How many in each pile? This is my fourth graders homework and I can't remember how to make the into an equation to be solved. Thanks so much for your help!!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let x, y, and z be the number of books in piles 1, 2, and 3.


Since there are "3000 books in three piles", this means that x%2By%2Bz=3000


Because " Pile 1 has 10 more books than pile 2", this tells us that x=y%2B10


Also, since "Pile 2 has twice as many as pile 3", this gives the equation y=2z



x%2By%2Bz=3000 Start with the given equation


%28y%2B10%29%2By%2Bz=3000 Plug in x=y%2B10


2z%2B10%2B2z%2Bz=3000 Plug in y=2z


10%2B5z=3000 Combine like terms on the left side.


5z=3000-10 Subtract 10 from both sides.


5z=2990 Combine like terms on the right side.


z=%282990%29%2F%285%29 Divide both sides by 5 to isolate z.


z=598 Reduce. So there are 598 books in the third pile

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y=2z Go back to the third equation


y=2%28598%29 Plug in z=598


y=1196 Multiply. So there are 1,196 books in the second pile


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x=y%2B10 Go back to the first equation


x=1196%2B10 Plug in y=1196


x=1206 Add. So there are 1,206 books in the first pile.



To check the answers, simply add up the books to get 3,000.