Question 192141: For each rational function, identify any holes or horizontal or vertical asymptotes of its graph.
y= -2(x-8)/(8-x)
I have tried a couple different things, but I am not sure if any of them are correct.
First attempt:
There would be a vertical asymptote at x=8.
There would be a horizontal asymptote at y=-2.
Second attempt:
There would be a hole at (8,2)
Third attempt:
There would vertical asymptote at x=8.
There would be a horizontal asymptote at y=2.
I am extremely confused any help would be greatly appreciated!
Answer by RAY100(1637)   (Show Source):
You can put this solution on YOUR website! good work
an easier approach might be
y=-2(x-8)/(8-x)
simplify to
y= 2(x-8) / (x-8)
cancelling (x-8) 's gives us y=+2 but with a hole at x=8
no vertical asymptotes ( ie den =0)
no real horizontal asymptotes except y does always =2
review of horiz asymptotes, y = a(n)x^n +..... / b(m) x^m +.....
if n less than m, hor asy at y=0
if n=m, hor asy at y=a(n)/b(m)
and if n>m, no hor asy
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