SOLUTION: subtract (x^2-2x-3)/(x^2-9x+18) - (x^2-5x-6)/(x^2+9x+8) it is two fractions and (x^2-2x-3) is the numerator of the first fraction and (x^2-5x-6) is the numerator of the s

Algebra ->  Rational-functions -> SOLUTION: subtract (x^2-2x-3)/(x^2-9x+18) - (x^2-5x-6)/(x^2+9x+8) it is two fractions and (x^2-2x-3) is the numerator of the first fraction and (x^2-5x-6) is the numerator of the s      Log On


   

Question 191964: subtract

(x^2-2x-3)/(x^2-9x+18) - (x^2-5x-6)/(x^2+9x+8)

it is two fractions and (x^2-2x-3) is the numerator of the first fraction and (x^2-5x-6) is the numerator of the second fraction


thank you!
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
(x^2-2x-3)/(x^2-9x+18) - (x^2-5x-6)/(x^2+9x+8)
(X-3)(X+1)/(X-6)(X-3)-(X-6)(X+1)/(X+8)(X+1)
CANCEL OUT THE (X-3) TERMS IN THE FIRST FRACTION & THE (X+1) IN THE SECOND FRACTION.
(X+1)/(X-6)-(X-6)/(X+8)
[(X+1)(X+8)-(X-6)(X-6)]/[(X-6)(X+8)]
[X^2+9X+8-(X^2-12X+36)]/(X-6)(X+8)
(X^2+9X+8-X^2+12X-36)/(X-6)(X+8
(21X-28)/(X-6)(X+8)
7X(3X-4)/(X-6)(X+8) ANS.