SOLUTION: simplify (n-6)/(n^2+11n+24) / (n+1)/(n+3) its a double division, i think, the first two problems (n-6)/(n^2+11n+24) is the numerator, and the second two problems are th

Algebra ->  Rational-functions -> SOLUTION: simplify (n-6)/(n^2+11n+24) / (n+1)/(n+3) its a double division, i think, the first two problems (n-6)/(n^2+11n+24) is the numerator, and the second two problems are th      Log On


   

Question 191957: simplify

(n-6)/(n^2+11n+24) / (n+1)/(n+3)


its a double division, i think, the first two problems (n-6)/(n^2+11n+24) is the numerator, and the second two problems are the denominator

Thank yoou
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

%28%28n-6%29%2F%28n%5E2%2B11n%2B24%29%29%2F%28%28n%2B1%29%2F%28n%2B3%29%29 Start with the given expression.


%28%28n-6%29%2F%28n%5E2%2B11n%2B24%29%29%28%28n%2B3%29%2F%28n%2B1%29%29 Multiply the first fraction %28n-6%29%2F%28n%5E2%2B11n%2B24%29 by the reciprocal of the second fraction %28n%2B1%29%2F%28n%2B3%29.


%28%28%28n-6%29%29%2F%28%28n%2B8%29%28n%2B3%29%29%29%28%28n%2B3%29%2F%28n%2B1%29%29 Factor n%5E2%2B11n%2B24 to get %28n%2B8%29%28n%2B3%29.


%28%28n-6%29%28n%2B3%29%29%2F%28%28n%2B8%29%28n%2B3%29%28n%2B1%29%29 Combine the fractions.


Highlight the common terms.


%28%28n-6%29cross%28%28n%2B3%29%29%29%2F%28%28n%2B8%29cross%28%28n%2B3%29%29%28n%2B1%29%29 Cancel out the common terms.


%28%28n-6%29%29%2F%28%28n%2B8%29%28n%2B1%29%29 Simplify.


%28n-6%29%2F%28n%5E2%2B9n%2B8%29 FOIL the denominator


So %28%28n-6%29%2F%28n%5E2%2B11n%2B24%29%29%2F%28%28n%2B1%29%2F%28n%2B3%29%29 simplifies to %28n-6%29%2F%28n%5E2%2B9n%2B8%29.


In other words, where n%3C%3E-8, n%3C%3E-3, or n%3C%3E-1