SOLUTION: a lot is in the shape of a triangle. The hypotenuse is 3 m longer than the longer leg. The longer leg is 6 m longer than twice the length of the shorter leg. Find the perimeter of
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-> SOLUTION: a lot is in the shape of a triangle. The hypotenuse is 3 m longer than the longer leg. The longer leg is 6 m longer than twice the length of the shorter leg. Find the perimeter of
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Question 191809This question is from textbook Beginning Algebra
: a lot is in the shape of a triangle. The hypotenuse is 3 m longer than the longer leg. The longer leg is 6 m longer than twice the length of the shorter leg. Find the perimeter of the lot. This question is from textbook Beginning Algebra
You can put this solution on YOUR website! let s = shortest leg
let l=longest leg = 2s+6
let h = hypt = l+3= (2s+6) +3 = 2s +9
hypt also allows right triangle therefore use pythagorous
c^2 = a^2 +b^2
(2s+9)^2= s^2 +(2s+6)^2
4s^2 + 36s +81 = s^2 + ( 4S^2 +24s +36)
collect like terms
0= s^2 -12s-45
factor
0= ( s+3) (s-15)
s= (-3) not possible
and s= (15)
check
triangle is 15 - 36 - 39 and pythagorous confirms ok
and finally per = 15+36+39 = 90
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