Question 191479: 35y^3-60y^2-20y
Factor the trinomial completely
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Start with the given expression
Factor out the GCF
Now let's focus on the inner expression
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Looking at we can see that the first term is and the last term is where the coefficients are 7 and -4 respectively.
Now multiply the first coefficient 7 and the last coefficient -4 to get -28. Now what two numbers multiply to -28 and add to the middle coefficient -12? Let's list all of the factors of -28:
Factors of -28:
1,2,4,7,14,28
-1,-2,-4,-7,-14,-28 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -28
(1)*(-28)
(2)*(-14)
(4)*(-7)
(-1)*(28)
(-2)*(14)
(-4)*(7)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -12? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -12
First Number | Second Number | Sum | 1 | -28 | 1+(-28)=-27 | 2 | -14 | 2+(-14)=-12 | 4 | -7 | 4+(-7)=-3 | -1 | 28 | -1+28=27 | -2 | 14 | -2+14=12 | -4 | 7 | -4+7=3 |
From this list we can see that 2 and -14 add up to -12 and multiply to -28
Now looking at the expression , replace with (notice adds up to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
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So our expression goes from and factors further to
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Answer:
So completely factors to
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