SOLUTION: Factor the trinomial completely 3x^2-20x-7

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Question 191471: Factor the trinomial completely
3x^2-20x-7

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at 3x%5E2-20x-7 we can see that the first term is 3x%5E2 and the last term is -7 where the coefficients are 3 and -7 respectively.

Now multiply the first coefficient 3 and the last coefficient -7 to get -21. Now what two numbers multiply to -21 and add to the middle coefficient -20? Let's list all of the factors of -21:



Factors of -21:
1,3,7,21

-1,-3,-7,-21 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to -21
(1)*(-21)
(3)*(-7)
(-1)*(21)
(-3)*(7)

note: remember, the product of a negative and a positive number is a negative number


Now which of these pairs add to -20? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -20

First NumberSecond NumberSum
1-211+(-21)=-20
3-73+(-7)=-4
-121-1+21=20
-37-3+7=4



From this list we can see that 1 and -21 add up to -20 and multiply to -21


Now looking at the expression 3x%5E2-20x-7, replace -20x with x-21x (notice x-21x combines to -20x. So it is equivalent to -20x)

3x%5E2%2Bhighlight%28x-21x%29-7


Now let's factor 3x%5E2%2Bx-21x-7 by grouping:


%283x%5E2%2Bx%29%2B%28-21x-7%29 Group like terms


x%283x%2B1%29-7%283x%2B1%29 Factor out the GCF of x out of the first group. Factor out the GCF of -7 out of the second group


%28x-7%29%283x%2B1%29 Since we have a common term of 3x%2B1, we can combine like terms

So 3x%5E2%2Bx-21x-7 factors to %28x-7%29%283x%2B1%29


So this also means that 3x%5E2-20x-7 factors to %28x-7%29%283x%2B1%29 (since 3x%5E2-20x-7 is equivalent to 3x%5E2%2Bx-21x-7)



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Answer:
So 3x%5E2-20x-7 factors to %28x-7%29%283x%2B1%29