SOLUTION: Given f(x) = e^-2x + 1, evaluate the following. Round to the nearest ten-thousandth. f(-1) f(3) f(-2) Show your work here: f(-1)=e -2(-1)+1=x-1 f(-1)=e^2+1 f(-1)=7.389

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Given f(x) = e^-2x + 1, evaluate the following. Round to the nearest ten-thousandth. f(-1) f(3) f(-2) Show your work here: f(-1)=e -2(-1)+1=x-1 f(-1)=e^2+1 f(-1)=7.389      Log On


   

Question 191051This question is from textbook
: Given f(x) = e^-2x + 1, evaluate the following. Round to the nearest ten-thousandth.
f(-1)
f(3)
f(-2)
Show your work here:
f(-1)=e -2(-1)+1=x-1
f(-1)=e^2+1
f(-1)=7.389+1
f(-1) = 8.389
 This question is from textbook

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming that the function is f%28x%29=e%5E%28-2x%29%2B1.


Evaluating f(-1):


f%28x%29=e%5E%28-2x%29%2B1 Start with the given equation.


f%28-1%29=e%5E%28-2%28-1%29%29%2B1 Plug in x=-1.


f%28-1%29=e%5E%282%29%2B1 Multiply -2 and -1 to get 2.


f%28-1%29=7.3891%2B1 Raise "e" to the 2nd power to get 7.3891 (note: this value is approximate).


f%28-1%29=8.3891 Add 1 to 7.3891 to get 8.3891.


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Evaluating f(3):


f%28x%29=e%5E%28-2x%29%2B1 Start with the given equation.


f%283%29=e%5E%28-2%283%29%29%2B1 Plug in x=3.


f%283%29=e%5E%28-6%29%2B1 Multiply -2 and 3 to get -6.


f%283%29=0.0025%2B1 Raise "e" to the -6th power to get 0.0025 (note: this value is approximate).


f%283%29=1.0025 Add 1 to 0.0025 to get 1.0025.


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Evaluating f(-2):


f%28x%29=e%5E%28-2x%29%2B1 Start with the given equation.


f%28-2%29=e%5E%28-2%28-2%29%29%2B1 Plug in x=-2.


f%28-2%29=e%5E%284%29%2B1 Multiply -2 and -2 to get 4.


f%28-2%29=54.5982%2B1 Raise "e" to the 4th power to get 54.5982 (note: this value is approximate).


f%28-2%29=55.5982 Add 1 to 54.5982 to get 55.5982.