SOLUTION: Every time I work these I get lost. I'm working out review of a crash class (7weeks) to take a final Friday and my confidence of understanding these is still not good.
Given f(x
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-> SOLUTION: Every time I work these I get lost. I'm working out review of a crash class (7weeks) to take a final Friday and my confidence of understanding these is still not good.
Given f(x
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Question 191041This question is from textbook Intermediate Algebra an Applied Approach
: Every time I work these I get lost. I'm working out review of a crash class (7weeks) to take a final Friday and my confidence of understanding these is still not good.
Given f(x) = e-2x + 1, evaluate the following. Round to the nearest ten-thousandth.
f(-1)
f(3)
f(-2)
Show your work here:
f(-1)=e -2(-1)+1=x-1
f(-1)=e^2+1
f(-1)=7.389+1
f(-1) = 8.389 This question is from textbook Intermediate Algebra an Applied Approach
You did the problem exactly right, so just keep doing what you are doing. The only thing you need to fix is that the question asked for the answer to the nearest ten-thousandth, and you reported to the nearest thousandth.
According to the Windows built-in calculator,
Rounded to the nearest ten-thousandth: 7.3891, so your answer should have been 8.3891.
If you have trouble translating nearest thousandth or nearest ten-thousanth to a number of decimal places, here's how I remember: If you write the number 10,000 there are 4 zeros, therefore you need 4 decimal places.
One other thing you might consider is using the sign when you say . Once you change something involving or any other irrational number into an actual number it is no longer truly equal no matter how many decimal places you use.
