SOLUTION: The area of a triangle is 96 sq. inches. Its altitude is 2 inches greater than five times its base. Find the altitude. ( A= 1/2bh )
I tried 96=1/2(5b)h
help please.
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-> SOLUTION: The area of a triangle is 96 sq. inches. Its altitude is 2 inches greater than five times its base. Find the altitude. ( A= 1/2bh )
I tried 96=1/2(5b)h
help please.
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Question 190818: The area of a triangle is 96 sq. inches. Its altitude is 2 inches greater than five times its base. Find the altitude. ( A= 1/2bh )
I tried 96=1/2(5b)h
help please. Found 2 solutions by edjones, nerdybill:Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! a=5b+2
ab/2=A
(5b+2)b/2=96
(5b+2)b=192
5b^2+2b=192
5b^2+2b-192=0
b=6 Quadratic formula (below)
a=32
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Ed
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You can put this solution on YOUR website! The area of a triangle is 96 sq. inches. Its altitude is 2 inches greater than five times its base. Find the altitude. ( A= 1/2bh )
.
Let b = base
then
5b-2 = altitude or height
.
therefore applying:
A= 1/2bh
we have
96 = (1/2)b(5b-2)
96 = (1/2)b(5b-2)
192 = b(5b-2)
192 = 5b^2 - 2b
0 = 5b^2 - 2b - 192
Apply the quadratic equation to solve for b (details below):
b = {6.464, -6.064}
We can toss out the negative solution so we get:
b = 6.464 inches (base)
.
To find the height or altitude:
5b-2 = 5(6.464)-2 = 30.32 inches (altitude)
.
Details of quadratic equation below:
.