SOLUTION: how do i solve this problem... Jackie wants to make a mixture of nuts to sell in her store consisting os hazelnuts and cashews.Hazelnuts cost $6.50 per pound and cashews cost $4.50
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Question 190632: how do i solve this problem... Jackie wants to make a mixture of nuts to sell in her store consisting os hazelnuts and cashews.Hazelnuts cost $6.50 per pound and cashews cost $4.50 per pound. If Jackie wants 60 pounds total os mixture and the cost to be $5.10 per pound,how many pounds of each will she need... please help me... Found 3 solutions by Alan3354, scott8148, mickeysexy13:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Jackie wants to make a mixture of nuts to sell in her store consisting os hazelnuts and cashews.Hazelnuts cost $6.50 per pound and cashews cost $4.50 per pound. If Jackie wants 60 pounds total os mixture and the cost to be $5.10 per pound,how many pounds of each will she need
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c + h = 60 (60 lbs of cashews and hazelnuts)
650h + 450c = 60*510 --> 13h + 9c = 612 (divide by 50)
c = 60-h (from 1st eqn)
Sub for c into 2nd eqn
13h + 9*(60-h) = 612
13h + 540 - 9h = 612
4h = 72
h = 18 lbs of hazelnuts
c = 42 pounds of cashews
You can put this solution on YOUR website! Jackie wants to make a mixture of nuts to sell in her store consisting of hazelnuts and cashews. Hazelnuts cost $6.50 per pound and cashews cost $4.50 per pound. If Jackie wants 60 pounds total of mixture and the cost to be $5.10 per pound, how many pounds of each will she need
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c + h = 60 (60 lbs of cashews and hazelnuts)
650h + 450c = 60*510 --> 13h + 9c = 612 (divide by 50)
c = 60-h (from 1st equation)
Sub for c into 2nd equation)
13h + 9(60-h) = 612
13h + 540 - 9h = 612
4h = 72
h = 18 lbs of hazelnuts
c = 42 pounds of cashews